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Mathematics 20 Online
OpenStudy (anonymous):

If an isosceles right triangle has as area of 2x^2+2x+1/2, what is its perimeter?

OpenStudy (aravindg):

what is the area of an isoceles right angled triangle ?

OpenStudy (anonymous):

[2x ^2+2x+1/2]

OpenStudy (aravindg):

lol not that I mean formula for area ?

OpenStudy (anonymous):

:))) aaa, hb/2 ??

OpenStudy (aravindg):

yep :) ...but note it is given isoceles so b=h !

OpenStudy (anonymous):

yeees, I know, but , ok Look==> If hb/2= 2x ^2+2x+1/2 so it would be hb= 4x^2+4x+1, theeen?

OpenStudy (aravindg):

well actually this is a tricky question ... give me a minute

OpenStudy (anonymous):

ok

OpenStudy (aravindg):

well first try simplifying the given quadratic :)

OpenStudy (aravindg):

tell me what you get?

OpenStudy (anonymous):

2(x+1)(x+1) ???

OpenStudy (anonymous):

noo, 2(x+1/2)(x+1/2) ?

OpenStudy (aravindg):

I get [(2x + 1)^2]/2 on simplification

OpenStudy (aravindg):

yep what you got is right

OpenStudy (aravindg):

I just took the two inside :)

OpenStudy (aravindg):

now area of any triangle is given by 0.5 *base * height...equate this to above eqn to get base=height = (2x+1) each..

OpenStudy (anonymous):

Thankss, you help me always, you are very kind :))

OpenStudy (aravindg):

yw :) ...can you do the rest ?

OpenStudy (anonymous):

yes I got it ))

OpenStudy (aravindg):

wow great ! :)

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