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Solve 2x2 - 8x = -7.
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2x2 - 8x - 7 = 0 solve quadratic ... and you should obtain 2 valuees for x :)
2x2-8x+7=0
plus 7 to the right side and using this formula -b +- (square root of b^2 - 4ac)/ 2ac
i still dont understand
2x^2 -8x +7 =0 right?
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then a =2 b = -8 and c = 7
its wrong
is that 2x^2 or (2x)^2 ?
my options are -2+square root 2 -2+2squate root 2 2+square root 2/2 or 2 +square root of 2 over 2
what are you talking about?
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