Question

A geometric sequence is
3
4
, 9, 108, 1296, 15,552, 186,624, ... . Which is the general term of the sequence?

Answer 1

a = 3 , d = 4/3
Tn = ar^ (n-1)
= 3 x 4/3 ( n-1 ) ??? hope i help

Answer 2

I'll post the answer choices.

Answer 3

ohh its 3/4 ... i thought 3, 4, 108 etc...

Answer 4

so you have a general formula for geometric sequences which is Tn = ar^(n-1)
suppose you have got a sequence like : 2 , 4 , 6 , 8 , 10
we denote the first term with letter "a" which = 2
and r is the common ration and = 2nd term divide by 1st term = 4 divide by 2 = 2
therefore : Tn = 4^(n-1)

Answer 5

ratio*
in your case :
a = 3/4 and r = 9 divide by 3/4
r=12
so general form : Tn = 3/4 ( 12) ^ (n-1)

Answer 6

Thank you so much. :D