Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

y = one thirdx − 3

y = one thirdx + 17

y = −3x − 3

y = −3x + 17

Answer 1

y=-3x+7
To become perpendicular: Has to be negative reciprocal
y=1/3x, can eliminate c and d

Answer 2

y=1/3x+b
-1=2+b
b=-3,
y=1/3x-3

Answer 3

Is it b or a?

Answer 4

a is the answer