Question

Find four consecutive integers such that the sum of the second and the fourth is 132.

Answer 1

well knowing they are consecutive equation is key.
you know that it will be n for the first and then n+1 for the next and so on.

Answer 2

1st #: n
2nd #: n+1
3rd #: n+2
4th #: n+3

Answer 3

(n+1)+(n+3)=132
2n+4=132
2n=128
n=64