Landon is standing in a hole that is 6.5 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y = –0.005x² + 0.45x – 6.5, where x is the horizontal distance of the rock, in meters, from Landon, and y is the height, in meters, of the rock above the ground. How far horizontally from Landon will the rock land? (1 point)
18.07 ft
35.96 ft
9.04 ft
71.93 ft

Question

Landon is standing in a hole that is 6.5 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y = –0.005x² + 0.45x – 6.5, where x is the horizontal distance of the rock, in meters, from Landon, and y is the height, in meters, of the rock above the ground. How far horizontally from Landon will the rock land? (1 point)
 18.07 ft 
35.96 ft 
9.04 ft
 71.93 ft

jim_thompson5910 · Answer

You basically have this parabola

|dw:1365120637602:dw|

jim_thompson5910 · Answer

the ground is here

|dw:1365120661304:dw|