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can somebody show me step by step how to find all the solutions for x^6 + 64 = 0
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(x^3 + 8)(x^3 - 8)
Think of it like this: \[(x^2)^3+(4)^3\]
Now factor it. It is the sum of two cubes.
It shows that the answers are \[\pm2i , \sqrt{3}\pm i , -\sqrt{3}\pm i \] how would i do that?? Sorry this stuff confuses me so much..
Did you factor it?
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how would you factor them if the first number is raised to two powers?
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