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Mathematics 18 Online
OpenStudy (anonymous):

2 sin 3θ − 1 = 0

OpenStudy (anonymous):

sin(3θ) = -1 => 3θ = 3π2, 7π/2 and 11π/2

OpenStudy (anonymous):

could you explain to me please how to find it? from where do I get 3pi/2 and the others

OpenStudy (anonymous):

yup yup right

OpenStudy (anonymous):

it go's like taht

OpenStudy (anonymous):

it's right you just add alll of it up

OpenStudy (sirm3d):

\[2\sin 3\theta-1=0\\2\sin 3\theta=1\\\sin 3\theta=1/2\\3\theta=?\]

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