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solve 8+ sqrt 2x≤5 the sqrt is only over 2x
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@jim_thompson5910 I got x≤9/2 for my anwer is that right?
\[\Large 8+\sqrt{2x} \le 5\] \[\Large \sqrt{2x} \le 5-8\] \[\Large \sqrt{2x} \le -3\] is that inequality ever true for any x value?
so Im correct right?
no
is \[\Large \sqrt{2x} \le -3\] ever true?
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no
so there are no solutions
ohh ok
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