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a right angled triangle ABC, right angled at B , prove that sinA / cosA = tan A and cosA / sinA = cot A
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|dw:1365173604947:dw| use the definitions
tan A = (a/c) = (a/b) / (c/b)
LHS= sinA=BC/AC cos A = AB/AC sinA/cosA=(BC/A)/(AB/AC)=BC/AB RHS= tanA=BC/AB hence, LHS= RHS
hmm...yes i have done sme method as @susan3 wrote
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