Find the electric field vector generate in point p(0,a) by a wire uniformly electrified with linear density equals to lambda above x axis. Consider as the vacumm means.

The result in the exercise is

((2*k0*lambda )/a) *(j vector)

But the result that I found is

(K0*x*lambda)/(a*sqrt(x^2+a^2)) *(j vector)

Thanks!!

Question

Find the electric field vector generate in point p(0,a) by a wire uniformly electrified with linear density equals to lambda above x axis. Consider as the vacumm means.

The result in the exercise is 

((2*k0*lambda )/a) *(j vector)


But the result that I found is

(K0*x*lambda)/(a*sqrt(x^2+a^2)) *(j vector)

Thanks!!

anonymous · Answer

$\lambda$ must be the charge density and not the current density and this is an "electrostatics problem" not dynamics..

anonymous · Answer

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