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What is the domain of the function
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\[y=3\sqrt{6x+42}\]
the term under square root should be greater than or equal to zero
When dealing with roots, the part under the radical must not be negative. So you start by solving that for 0 and the domain is directly related to that.
solve that inequality to get the domain
how?
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\[6x+42 \ge 0\] solve for x
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