Find the ratio of the width of a regulation size basketball court to its perimeter. 50 ft (width) 94 ft (length)

Question

anonymous · Answer

|dw:1365192832158:dw|

bbb911 · Answer

what i did was add 50 and 50 then added 94 and 94 but i think its wrong

anonymous · Answer

yes. thats good. that is your perimeter P

what they are asking for is the ratio of P to width

just divide the numbers like above!

anonymous · Answer

sorry
ratio of width to perimeter
so,
$${w\over p}={50\over \text{that what you've got}}=?$$

bbb911 · Answer

so i get 288 right when all of them are added up

anonymous · Answer

yep. thats your "p"
now find the ratio

bbb911 · Answer

okay since it is my perimeter how do i get the ratio i know the above says w over p so do i divided the length or width my 288

anonymous · Answer

no

just this:

width divided by the perimeter 

this is also said as "ratio" of width to perimeter

bbb911 · Answer

so i divide width by perimeter and since the width is 50 i will divide 288 to 50 right?

anonymous · Answer

they are specifically asking for "width" so, you do not have a choice
... :/
width / perimeter

bbb911 · Answer

will it come up to 5 38/50?