Question

Find the factors of 3a2 + 14a − 24.

Answer 1

Madam Can I solve it for you ?

Answer 2

Madam See

Q = 3a^2 - 14a - 24
3Q = 9a^2 - 14(3a) - 72
3Q = ( 3a)^2 - 14(3a) - 72
Let u = 3a
3Q = u^2 - 14u - 72
3Q = ( u - 18 )(u + 4 )
3Q = ( 3a - 18 )(3a + 4 )
3Q = 3(a - 6 )(3a + 4 )
Q = ( a - 6 )(3a + 4 )

Answer 3

@Gabylovesyou there is Another way of doing this is.... wanna know ?

Answer 4

thats not one of my choices.... yes

Answer 5

[ ( -14 / 2 ) - k ] [ ( - 14 / 2 ) + k ] = 3( - 24 )
( - 7 - k ) ( - 7 + k ) = - 72
49 - k^2 = - 72
121 = k^2
11 = k

- 7 - 11 = - 18
- 7 + 11 = 4

3a^2 - 18a + 4a - 24
= 3a( a- 6 ) + 4 ( a - 6 )
= ( 3a + 4 ) ( a - 6 )

Answer 6

Is it ok now ?

Answer 7

no... lol

Answer 8

Now last option, @nader1 My friend please Help Gaby Madam.

Answer 9

ok wait let me read everything

Answer 10

3a^2 + 14a − 24
3a^2 + 18a - 4a - 24
(3a - 4) (a + 6)

Answer 11

anytime :)

Answer 12

tell me :) gaby

Answer 13

On Behalf of Gaby Madam Thankyou @nader1

Answer 14

anytime i wait to see if i am correct but i am sure

Answer 15

3a^2+14a-24


3a^2+18a-4a-24


(3a^2+18a)+(-4a-24)


3a(a+6)+(-4a-24)


3a(a+6)-4(a+6)


(3a-4)(a+6)



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3a^2+14a-24


completely factors to


(3a-4)(a+6)