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cosx/1-tanx + sinx/1-cotx
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find ... ?
I know the answer I'm just having a hard time getting to it... sin(x)+cos(x)
so proof : cosx/1-tanx + sinx/1-cotx = sin x + cos x
exactly
tan x = sin x / cos x , cot x = cos x / sin x, (cos x) / (1 - tan x) + (sin x) / (1- cot x) = (cos x) / (1 - ((sin x) / cos x)) + (sin x)(1 - ((cos x)/sin x)) = (cos² x)/(cos x - sin x) + (sin² x) / (sin x - cos x) = cos² x - sin² x) / (cos x - sin x) = (cos x + sin x)(cos x - sin x) / (cos x - sin x) = cos x + sin x
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If you dont understand some part just ask.. i ll try to help as much as possible .. good luck
appreciate the help thank you... and yeah I'll probably be asking
Got it thank you so much...
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