Question

A stone is launched vertically upward from a cliff 256ft above the ground at a speed of 96 ft/s. Its height above the ground t seconds after the launch is given by s= -16t^2 + 96t +256 for 0<_t<_8. When does the stone reach its maximum height?

Answer 1

@MATTW20 can you help please

Answer 2

find the first derivative. set that equal to zero and solve to find the critical point. Once you do that let me know what you have and I'll tell you where to go from there

Answer 3

almost finished?

Answer 4

is it 3 seconds?

Answer 5

are you asking for the critical point or the answer when you say 3 seconds?

Answer 6

the answer is 3 seconds?

Answer 7

yes

Answer 8

yay...ok I understood that one. Stay close I have more Qs :)

Answer 9

ok