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Geometry 13 Online
OpenStudy (anonymous):

Help! Find the area of the triangle and solve for x Pic below

OpenStudy (anonymous):

|dw:1365221928554:dw|

OpenStudy (anonymous):

use Heron's formula for the area \[A=\sqrt{s(s-a)(s-b)(s-c)}\qquad,s={a+b+c\over2}\]

OpenStudy (anonymous):

\[s={13+5+12\over2}=?\]

OpenStudy (anonymous):

15

OpenStudy (anonymous):

good then, \[A=\sqrt{15(15-13)(15-5)(15-12)}=?\]

OpenStudy (anonymous):

i only take 15(15-13) not the whole thing right?

OpenStudy (anonymous):

no the whole thing

OpenStudy (anonymous):

\[A=\sqrt{15\times2\times10\times3}=?\]

OpenStudy (anonymous):

so just 15*(2)(10)(3)

OpenStudy (anonymous):

ok that's what i thought

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

so 900

OpenStudy (anonymous):

forgot the suqre-root.. :)

OpenStudy (anonymous):

30 is that for x

OpenStudy (anonymous):

nope thats the "Area"

OpenStudy (anonymous):

oooh ok

OpenStudy (anonymous):

now, we also have the old formula \[A={1\over2}\times{\rm base}\times{\rm height}\\30={1\over2}\times13\times x\]

OpenStudy (anonymous):

so divide 30 by 13

OpenStudy (anonymous):

yes, solve for "x"

OpenStudy (anonymous):

x=4.61

OpenStudy (anonymous):

yep. those are the things you are asked.

OpenStudy (anonymous):

alright alright thank you very much

OpenStudy (anonymous):

yer welcome.

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