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Help! Find the area of the triangle and solve for x Pic below
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|dw:1365221928554:dw|
use Heron's formula for the area \[A=\sqrt{s(s-a)(s-b)(s-c)}\qquad,s={a+b+c\over2}\]
\[s={13+5+12\over2}=?\]
15
good then, \[A=\sqrt{15(15-13)(15-5)(15-12)}=?\]
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i only take 15(15-13) not the whole thing right?
no the whole thing
\[A=\sqrt{15\times2\times10\times3}=?\]
so just 15*(2)(10)(3)
ok that's what i thought
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yep
so 900
forgot the suqre-root.. :)
30 is that for x
nope thats the "Area"
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oooh ok
now, we also have the old formula \[A={1\over2}\times{\rm base}\times{\rm height}\\30={1\over2}\times13\times x\]
so divide 30 by 13
yes, solve for "x"
x=4.61
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yep. those are the things you are asked.
alright alright thank you very much
yer welcome.
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