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OpenStudy (anonymous):

Help! Find the area of the trapezoid pic below

OpenStudy (anonymous):

same exact thing :)

OpenStudy (anonymous):

|dw:1365228249435:dw|

OpenStudy (anonymous):

i thought so is it A=1/2 (9)(6)

OpenStudy (anonymous):

something dont look right in the diages.. both cannot be right angles!!

OpenStudy (anonymous):

they are in the book

OpenStudy (anonymous):

then this way |dw:1365221203499:dw|

OpenStudy (anonymous):

do you see the parallel sides? - what are they do you see the height? how much

OpenStudy (anonymous):

6 and 5 are parallel and the hight is 9

OpenStudy (anonymous):

good Area = (1/2) * (SUM of the two parallel sides) * height

OpenStudy (anonymous):

A=1/2 (11)(9) 49

OpenStudy (anonymous):

perfecto.

OpenStudy (anonymous):

that's right!

OpenStudy (anonymous):

what!? wait

OpenStudy (anonymous):

thats like this!!!!!!!!!! \[11\times9\over2\]

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