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i dont know she asked me to see my answer again precisely review
\[m <A=\frac{1}{2}(arc BC-arc BD)\] \[14=\frac{1}{2}(112-arc BD)\]
\[28=112-arc BD\]
\[-84=-arc BD\]
\[arc BD = 84\]
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arc BD=x
Arc CD = 360-112-84=164
\[y= \frac{1}{2}(164)=82\]
I'm not finding a V anywhere. Where is it. Can you point it out to me?
sorry its the web page let me reload
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thanks mertsj
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