Question

C++

Task: http://screencast.com/t/4EDESKcj

Code for the Task:http://pastebin.com/jrFCimga

Error I am getting: http://screencast.com/t/ndEPszkq


Why am I getting this Error?? I don't understand??

Answer 1

@dumbsearch2 Get over here now...i know you can do this...

Answer 2

Help me someone please, I know there is a detail I am missing and its driving me crazy...

Answer 3

@dumbsearch2 Is like a wizard...he is just slow as heck

Answer 4

What do you mean @dumbsearch2 ? Like what looping macro ???

Answer 5

Your using the variables without giving them their "default" value.

This warning will go away if you do this:
int k = 0;
for each variable.
k being the variable name.

Answer 6

Tell me if that works, or helps.

Answer 7

Though please note that I have only started picking up C++ in the past week, PHP, Java and the web languages are what I'm best at.

Answer 8

Bro now its letting me run the program but It doesn't work, for example what ever variable I enter to the program, it doesn't display anything

Answer 9

@dumbsearch2

Answer 10

What errors do you see left ?
or warnings

Answer 11

There are no further syntax errors left, the program just doesn't work correctly. @dumbsearch2

Answer 12

@opcode
He's an expert at C++!

But huh!
This is so weird...

Answer 13

Please help me guys :(

Answer 14

http://www.stackoverflow.com/

Answer 15

Dude what is this?

Answer 16

It's so easy to sign up.
It's the biggest programming forum.
You get the answers in 1-5 minutes.
StackOverflow

Answer 17

You have a few problems with that code. I'm surprised that you got a compile out of it. Blocks of code, a block being more than one line, need to be started and ended with curly brackets ( "{}" ). It will also help the readability of your code, and it needs it.

Your if() statements are logically wrong. They're comparing a variable a against an uninitialized variable. You probably want to compare to a literal value:

if (a == 'd' || a == 'D' )
{
// do something
}

There may be a problem in your if() statements that comes down to operator precedence. In complex condtionals like above, I was taught to write them:

if( (a == 'd' ) || ( a == 'D' ) )
{
}

which would || the results of the two ==. Without the parentheses, I'm not sure that || would evaluate after ==.