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OpenStudy (anonymous):
logx^3=(logx)^2 solve for x
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OpenStudy (anonymous):
3logx = (log x)^2 log x (log x - 3) = 0 log x = 0 or log x = 3 x = 1 or e^3
OpenStudy (anonymous):
yeah @Kanwar245 has it :)
OpenStudy (anonymous):
I meant|dw:1365283288597:dw|
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