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OpenStudy (anonymous):
10^(2x+3)=315 Solve for x
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OpenStudy (anonymous):
\[10^{(2x+3)}=315\] since "x" is in the exponent, we hve to bring it down so, take a \(\log_{10}\) on both sides
OpenStudy (anonymous):
2x+3=log315? But then what?
OpenStudy (anonymous):
\[2x=\log315-3 \] take a calculator, find the numbers...
OpenStudy (anonymous):
No other way?
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