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Mathematics
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trigonometry
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@Mertsj
\[5(\cos y+\sin y)(2\cos y-\sin y)=7\]
\[5(2\cos ^2y-\sin y \cos y+2\sin y \cos y-\sin ^2y)-7=0\]
when I expand it, this is what I get, \[10\cos ^{2}y+5sinycosy-5\sin ^{2}y-7=0\]
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Yep. Me too. But that doesn't seem very helpful/.
i found it! thank you for your help....
What did you do?
divide through by cos^2 y and what do you get??
Oh. of course. Good going!!
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this is what I got, \[10+5tany-5\tan ^{2}y-7\sec ^{2}y=0\] \[10+5tany-5\tan ^{2}y-7(\tan^{2}y+1)=0\] from there, I arrived at the answer..
exactly. Very good.
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