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Find the sample space for tossing 2 coins. Then find P(exactly 1 head)
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\[ \Omega = \{(h,h), (h,t), (t,h), (t,t)\} \\ A = \{(h,t), (t,h)\} \\ \Pr(\text{heads}=1) =\Pr(A) =\frac{|A|}{|\Omega|} \]
The sample space is 4 and P(of 1 head) is 2/4 or 1/2
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