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OpenStudy (anonymous):
Anytime a circle is inscribed within any quadrilateral, the following equation holds: AC+BD=CD+AB. Why?
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Directrix (directrix):
Please post the diagram. @tjbtn
OpenStudy (anonymous):
|dw:1365307726667:dw|
Directrix (directrix):
I think that the answer (proof) has to do with the theorem that tangents drawn to a circle from an outside point are congruent.
Directrix (directrix):
If a circle is inscribed in a polygon, then the sides of the polygon are tangent to the circle. |dw:1365308048763:dw|
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