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If AB=7, what is the area between the two circles?
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Suppose the two circles are concentric. CB = 7/2 = 3.5 (line joining from centre perpendicular to chord bisects chord) By Pyth. Thm., \[r_2^2 = r_1^2 + 3.5^2\]So, \[r_2^2 - r_1^2 = 3.5^5\] Area between two circles = area of big circle - area of small circle \[= \pi (r_2^2 - r_1^2)\]The rest are substitution and calculations.
*facepalm* For the sixth line, it should be \[r_2^2 - r_1^2 = 3.5^2\]
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