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Factor completely: 3bx2 − 9x3 − b + 3x
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Right, I take it for -9x^3+3bx^2+3x-b=0 I guess?
So, here's what I do. -3x(3x^2-1) + b( 3x^2-1) = 0 => (b-3x)(3x^2-1)=0
By now, the answer should be obvious.
@NeetziD If we are factoring, then why set the expression equal to zero as if we were finding the roots? Would the solution not end here: --> (b-3x)(3x^2-1) >>Factor completely: 3bx2 − 9x3 − b + 3x
@Directrix Sorry... took it for a equation. =P didn't notice the factor bit... dumbed down there
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Hey, no need to be sorry about anything. I was just asking. And, on that open cone question the Asker said is wrong, I got the same thing you did.
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