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Find the value of 7x^2 / sqrt x^5 7 sqrt x / x 7 /x 7 sqrt x 7x / sqrt x
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\(\frac{7x^2}{\sqrt{x^5}}\) Remember that \(\sqrt{x^y}\) = x^(y/2)
ok but im still puzzeled
sqrt of x^5 is x^2*sqrtx. So, this gives 7/sqrtx
\[\Large{7x^2\over x^{5\over2}}=7x^2\times x^{-5\over2}=7\times x^{2-{5\over2}}\]
@electrokid Your LaTeX is better than me. :P
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\[=\Large{7\times x^{4-5\over2}}=7\times x^{-1\over2}={7\over x^{1\over2}}\]
@tyteen4a03 :D. That is what I use all the time. Got rid of "Office suites" a long time ago
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