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Algebra One Help: Question Below! :)
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A 10−gallon container of water costs (y + 2) dollars while a 5−gallon container of water costs (y − 2) dollars. If the price per gallon of water is the same for both containers, the equation below can be used to solve for y. y+2/10 = y-2/5
are you sure that is the equation
\[\frac{ y + 2 }{ 10 } = \frac{ y - 2 }{ 5 }\]
y=6
you multipy both sides to find a common denominator
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oops I forgot the question.
What is the value, in dollars, of y?
Correct equations. y = $6. Price per gallon is $0.8.
yea
the value of y is 6?
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yes here let me show you
y+2/10=y-2/5 5(y+2/10)=5(y-2/5)
you get 5y+10/50=10y-20/50
multiply each side by 50 to cancel them out
your left with 5y+10=10y-20
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-5y=-30 y=6
did you get it?
yeah.
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