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X2 + 10x + 24
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You want it simplified, right?
Are you trying to factor this??
Should it look like \[x ^{2}+10x+24\]
To check of the roots of an equation ax^2+bx+c=0 are real:- b^2-4ac=/>0 Here it is 10^2-4(1)(24) which is 4. Well your equation has real roots.
The square root of that expression is D. So, here's how you do it, x has values, (-b+/-D)/2a that is, -10+2/2 or -10-2/2 that is -4 or -6.
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Your equation is (x+4)(x+6)=0 and if none of that. It's just simply (x+4)(x+6)
What @NeetziD said :)
:) Thankyou.
@NeetziD You're welcome :)
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