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Mathematics 23 Online
OpenStudy (anonymous):

X2 + 10x + 24

OpenStudy (anonymous):

You want it simplified, right?

OpenStudy (anonymous):

Are you trying to factor this??

OpenStudy (anonymous):

Should it look like \[x ^{2}+10x+24\]

OpenStudy (anonymous):

To check of the roots of an equation ax^2+bx+c=0 are real:- b^2-4ac=/>0 Here it is 10^2-4(1)(24) which is 4. Well your equation has real roots.

OpenStudy (anonymous):

The square root of that expression is D. So, here's how you do it, x has values, (-b+/-D)/2a that is, -10+2/2 or -10-2/2 that is -4 or -6.

OpenStudy (anonymous):

Your equation is (x+4)(x+6)=0 and if none of that. It's just simply (x+4)(x+6)

OpenStudy (anonymous):

What @NeetziD said :)

OpenStudy (anonymous):

:) Thankyou.

OpenStudy (anonymous):

@NeetziD You're welcome :)

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