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How do I completely factor x^2-8x+16?
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what multiply equals 16 and add together to equal 8?
basically what two numbers a) multiply to 16 AND b) add to -8 at the same time
Would it be (x+4) than?
yea!
-4 and -4 add to -8 and they multiply to 16 so it's really (x-4)(x-4) or (x-4)^2
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no, its 4
Yes exactly what can you multiply to get 16 but add to -8? \[ x^2-8x+16\] \[(x-4)(x-4)\] \[(x-4)^2\]
thanks guys!
yw :)
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