Question

b^2-9b-11=3

Answer 1

b^2-9b-11=3
subtract by 3 to both sides giving us
b^2-9b-11-3=3-3
b^2-9b-14=0
factor out fot the left side
(b-2)(b-7)=0
for the zeroes, take each factor make be equal zero

b-2=0
add by 2 to both sides :
b-2+2=0+2
b=2

b-7=0
add by 7 to both sides :
b-7+7=0+7
b = 7

the solution is {2,7}
i assumed u need factorization method