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6x^3-14x^2-12x factor trinomial completely
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@RadEn
take the common, is x
so, it can be x(6x^2 - 14x -12)
sorry, i think the common should 2x, therefore = 2x(3x^2 - 7x - 6)
what else is common?
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now factor within ( )
now, factor out which in bracket (3x^2 - 7x - 6) = (3x + 2)(x - 3)
so, 6x^3-14x^2-12x = 2x(3x + 2)(x - 3)
yup
2x(3x+2)(x-3)
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2x(3x+2)(x-3)
yes, or u can modif again... 2x(3x+2)(x-3) = x(6x+4)(x-3) = x(3x+2)(2x-6) they are is same :)
all these would be factored completely?
actually, yes just choice in ur options there
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