Question

Please help!

Answer 1

Is the correct answer A?

Answer 2

No, use F.O.I.L

Answer 3

\[\Huge (\sqrt{14}-2\sqrt{2})^2 \\ \\ FOIL \\ \\ \Huge 14-2\sqrt{28}-2\sqrt{28}+4(2)\]
Can you finish it here?

Answer 4

@.Sam. thank you. What do I do with the square roots? :(

Answer 5

The roots stays like a variable, \[\Huge 14-2\sqrt{28}-2\sqrt{28}+8 \\ \\ \Huge 22-4\sqrt{28} \\ \\ \Huge 22-4\sqrt{4*7} \\ \\ \Huge 22-4\sqrt{4}\sqrt{7} \\ \\ \\ \\ \Huge 22-8\sqrt{7}\]

Answer 6

Thank you so much!!!

Answer 7

Welcome :)