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\[\frac{ \left( 1+\cot \theta+\tan \theta \right)\left( \sin \theta-\cos \theta \right) }{ \sec ^{3 }\theta -cosec ^{3} }\]
\[=\sin^{2}\theta \cos ^{2}\theta\]
put everything in terms on sin and cos
yes, but isn`t there any easy method with the trigonometric relations
thats it...
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