Question

Simplify:
(1 / x)^-n

...how?

Answer 1

ok\[\frac{1}{x}=x^{-1}\]so\[(\frac{1}{x})^{-n}=(x^{-1})^{-n}=x^{(-1)(-n)}=x^n\]does that help?

Answer 2

See
http://www.khanacademy.org/math/arithmetic/exponents-radicals/world-of-exponents/v/negative-exponent-intuition

for a short video that explains why...

Answer 3

thanks!