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Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 I close parentheses minus open parentheses 6 minus 6 I close parentheses
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\[\sqrt{-9} / (4-7i)-(6-6i)\]
solve the first parentheses and get the square root of -p which should give you 3/3=1 so its 1- (6-6i) which is 0 so its 1-0 = -1
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