Question

Use the method of substitution to solve the system.

x^2+ y^2 = 8
y − x = 4

Answer 1

y − x = 4

y = 4 + x

Answer 2

x^2+ y^2 = 8

x^2+ (4+x)^2 = 8

x^2 + 16 + 8x + x^2= 8

2x^2 + 8x + 16 = 8

2x^2 + 8x + 16 - 8 = 0

2x^2 + 8x + 8 = 0

2(x^2 + 4x + 4) = 0

x^2 + 4x + 4 = 0

I'll let you finish up