Question

Please help me with this

Answer 1

the answer choices are:
A) 5
B) 1
C) 3
D) -1

Answer 2

\[\large \sqrt{2x-1}=x-2\]


\[\large (\sqrt{2x-1})^2=(x-2)^2\]


\[\large 2x-1=(x-2)^2\]


\[\large 2x-1=x^2 - 4x + 4\]


\[\large 0=x^2 - 4x + 4-2x+1\]


\[\large x^2 - 6x + 5 = 0\]


I'll let you finish

Answer 3

Make sure you check your potential answer(s)