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Find sin(x) if cos(x)=a/a+2.
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a) \[\frac{ 2\sqrt{a+1} }{a+2 }\] b) \[\frac{ 4(a+1) }{a+2 }\] c) \[\frac{ 2\sqrt{a+1} }{a }\] d) \[\frac{ 4(a+1) }{ a }\]
e) \[\frac{ \sqrt{a+1} }{ 2a }\]
\[\sin ^2x+\cos ^2x=1\]
\[\sin ^2x+(\frac{a}{a+2})^2=1\]
\[\sin ^2x=1-\frac{a^2}{(a+2)^2}=\frac{(a+2)^2-a^2}{(a+2)^2}=\]
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\[\frac{a^2+4a+4-a^2}{(a+2)^2}=\frac{4(a+1)}{(a+2)^2}\]
\[\sin x=\frac{2\sqrt{a+1}}{a+2}\]
Thank you so much!
yw
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