Question

the sum of the squares of two consecutive positive odd inteegers is 202 find the numbers

Answer 1

guess and check

Answer 2

i did and it didnt add up

Answer 3

\(7^2+9^2=49+81\) is too small, try \(9^2+11^2\)

Answer 4

also let x = number 1
let number 2 = x +2

x^2+(x+2)^2=202

the positive root will give you x=9,

therefore the numbers are 9 and 11

Answer 5

x^2 + (x +2)^2 = 202