What are the real or imaginary solutions of the polynomial equation?
x^3 = 216
1) –6, 3 + 3isqrt7, and 3 – 3isqrt7
–6, 3 + 3isqrt3, and 3 – 3isqrt3
6, 3 + 3isqrt7, and 3 – 3isqrt7
6, –3 + 3isqrt3, and –3 – 3isqrt3

Question

What are the real or imaginary solutions of the polynomial equation?
x^3 = 216
1) –6, 3 + 3isqrt7, and 3 – 3isqrt7
–6, 3 + 3isqrt3, and 3 – 3isqrt3
6, 3 + 3isqrt7, and 3 – 3isqrt7
6, –3 + 3isqrt3, and –3 – 3isqrt3

phi · Answer

you can rule out the choices with -6  because -6*-6*-6  will be negative.

phi · Answer

I would plot all 3 roots  for the remaining 2 choices...    the roots for this problem will be evenly spaced around the origin.