Question

Log6 1/1296=-4

Answer 1

What is the base?

Answer 2

the equation is correct...

\[\log_{6}( \frac {1}{1296}) = \log_{6} (\frac{1}{6^4}) = \log_{6}(6^{-4})\]

and using the log laws

\[\log_{a}(a^n) = n\]

Answer 3

@campbell_st
Does the asker know what the base and the exponent are?

Answer 4

Thats a good question, but we may be waiting for a reply...