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Mathematics 8 Online
OpenStudy (anonymous):

12x^2y-6xy+4x^2/2xy

OpenStudy (anonymous):

What are you looking for? The roots?

OpenStudy (anonymous):

No, how to factor it completely?? I tried but I can't get the right answer,

OpenStudy (anonymous):

I get: -6 x y+12 x^2 y+2 x^3 y that is with it =0

OpenStudy (anonymous):

Thank you!!!!!

OpenStudy (anonymous):

That is assuming, the attached is your equation, thats what i took from what you posted

OpenStudy (anonymous):

Yes it is thanks!

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