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Algebra 19 Online
OpenStudy (anonymous):

i need help

OpenStudy (anonymous):

With what?

OpenStudy (anonymous):

OpenStudy (anonymous):

@help123please.

OpenStudy (anonymous):

@electrokid

OpenStudy (anonymous):

Oh, sorry, I don't know how to do that.

OpenStudy (anonymous):

3x ^2 - 6 = 10 - x ^2 @help123please.

OpenStudy (anonymous):

I don't understand. Sorry.

OpenStudy (raden):

3x^2+11x+6=0 factor out! (3x+2)(x+2)=0 can u get x ?

OpenStudy (raden):

opps typo. it should like this (3x+2)(x+3)=0

OpenStudy (anonymous):

x=5/3

OpenStudy (raden):

to get x, take each factor them make be equal zero

OpenStudy (raden):

3x+2=0 how do u solve this ?

OpenStudy (anonymous):

subtract two

OpenStudy (raden):

yes, then ?

OpenStudy (anonymous):

divide by three

OpenStudy (raden):

so, what's the value of x ? it just the 1st

OpenStudy (anonymous):

@RadEn

OpenStudy (raden):

hah, did u solve question before ?

OpenStudy (anonymous):

yes but i have to corrected it @RadEn

OpenStudy (raden):

okay, just confirm the answer is the first one {-2/3, -3}

OpenStudy (anonymous):

i got that i need help with this one

OpenStudy (raden):

which one, the 2nd or the 3rd ? :P

OpenStudy (anonymous):

this

OpenStudy (raden):

(x+4)/4 = x/(x-2) do cross multiply (x-2)(x+4) = 4x simplify! x^2 + 2x - 8 = 4x x^2 + 2x - 4x - 8 = 4x - 4x x^2 - 2x - 8 = 0 factor out! (x-4)(x+2) = 0 find the zeroes

OpenStudy (anonymous):

4 and -2

OpenStudy (raden):

correct!

OpenStudy (anonymous):

3x ^2 - 6 = 10 - x ^2

OpenStudy (anonymous):

@RadEn

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