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xcosy=1 Implicit Differentiation
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xcosy=1 cosy + x(-siny)y' = 0 cosy - (xsiny)y' = 0 cosy = (xsiny)y' y ' = cosy/xsiny = (1/x) * coty
he is right...do you want explanation?
I think I understood it, but please feel free to explain.
The product rule is used to find the derivative and then solve for y'
Why is x multiplied into -siny?
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xcosy=1 diff. w.r.t. x cosy+x(-siny)y'=0 or cosy=xsiny y' y'=cosy/xsiny
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