Question

Graph the equation : x^2+3y^2=2...Find where it cuts the axes(x-axis and y-axis) etc...

Answer 1

x^2+3y^2=2
x^2/2+3y^2/2=1
x^2/2+y^2 /2/3 =1
which is an ellipse

Answer 2

x^2+3Y^2=2
it cuts x-axis where y=0
x^2=2
x=±√2
it cuts x-axis at(±√2,0)
it cuts y-axis where x=0
3y^2=2
y^2=±√(3/2)
it cuts y axis at(0,±√(3/2) )