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Mathematics 18 Online
OpenStudy (anonymous):

Can anyone explain how to solve(factor) this?

OpenStudy (anonymous):

\[16s ^{4} - 81\]

OpenStudy (anonymous):

(4s^2-9)(4s^2+9)

OpenStudy (inkyvoyd):

a^2+b^2=(a+b)(a-b) hint: touseii did not give you the complete factoriazation. 4s^2-9 can still be factored.

OpenStudy (anonymous):

(2s - 3)(2s + 3) ? @inkyvoyd

OpenStudy (inkyvoyd):

yeah touseii.

OpenStudy (anonymous):

would it be (2s - 3)(2s + 3)^2 because that way you get the original binomial?

OpenStudy (inkyvoyd):

no. It'd be (2s-3)(2s+3)(4s^2+9)

OpenStudy (anonymous):

ohh okay i understand

OpenStudy (inkyvoyd):

irreducible (with complex numbers) factorization would be \((2s-3)(2s+3)(2s-3i)(2s+3i)\)

OpenStudy (anonymous):

okay makes sense thanks(:

OpenStudy (inkyvoyd):

np xD

OpenStudy (anonymous):

Thanks a lot!!!

OpenStudy (anonymous):

Welcome(: but it was @inkyvoyd who really helped

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