can someone help me pleaseeee 5^2+19z-4

Question

imtant · Answer

Do you want to find z?right?

anonymous · Answer

yes

imtant · Answer

If that so,the solution like this..19z=-25+4, then you get 19z=-21,and finally z=-21/19..

anonymous · Answer

i dont get it o.O

imtant · Answer

5^2+19z-4=0 (bring 5^2 to the right and change to - value,same goes to -4 that then be +4, like this..
19z=-25+4 and now solve like it.
19z=-21 and z equal to -21/19..Is that clear?

anonymous · Answer

so the answer is -21 thats it?

imtant · Answer

No.it is -21/19..because you need to find z..so 19 must bring to the right..that will become division..ok?

anonymous · Answer

ok so i would have to divide it or leave it like that ?

imtant · Answer

you can leave it like that.

anonymous · Answer

oh ok thank you

directrix · Answer

Is the problem supposed to be this: Solve z^2 + 19z - 4 = 0 for z? Just wondering.
@naomi_29

imtant · Answer

Yw..

anonymous · Answer

i wrote the question wrong it was supposed to be 5z^2+19z-4

directrix · Answer

What are the instructions for the problem?

imtant · Answer

So you need to factorize it..

imtant · Answer

There will be two answers..that is 1/5 and-4..

anonymous · Answer

yes i need factors

directrix · Answer

>yes i need factors

>>that is 1/5 and-4..
These are roots, not factors.

imtant · Answer

the factors are (5z-1)(z+4)..right?