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A table for y=x^2-9 is given below. Solve each equation or inequality. a. x^2-9=0 b. x62-9<0 c. x^2-9>0 table: x: -4 -3 -1 0 1 3 4 y: 7 0 -8 -9 -8 0 7
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@bahrom7893 ??
@satellite73 ive had a long day at work and im kinda not functioning that well, can u take up on this one?
lol
\[x^2-9=0\] \[(x-3)(x+3)-0\] \(x=3\) or \(x=-3\)
for \(x^2-9<0\) it will be all values of \(x\) between the zeros, that is any \(x\) that satisfies \[-3<x<3\]
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for \(x^2-9>0\) it is everything else
So x<-3 or x>3
right
you guys are the best! Bare with me, This is my math final then after that I am DONE with math!
never
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oh yes my degree is in healthcare administration... no hard math
there will always be math, trust me
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